11-2x=x^2+4x+4

Solution for 11-2x=x^2+4x+4 equation:

11-2x=x^2+4x+4

We move all terms to the left:

11-2x-(x^2+4x+4)=0

We get rid of parentheses

-x^2-2x-4x-4+11=0

We add all the numbers together, and all the variables

-1x^2-6x+7=0

a = -1; b = -6; c = +7;
Δ = b2-4ac
Δ = -62-4·(-1)·7
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-8}{2*-1}=\frac{-2}{-2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+8}{2*-1}=\frac{14}{-2}
=-7
$